What is the derivative of (8x+5^2) ?

The derivative of (8x+5^2) is 16(8x+5)

What is the first derivative of (8x+5^2) ?

The first derivative of (8x+5^2) is 16(8x+5)

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\frac{d}{d x} ((8 x + 5)^{2})

16 (8 x + 5)

Solution steps

\frac{d}{d x} ((8 x + 5)^{2})

Apply the chain rule:

2 (8 x + 5) \frac{d}{d x} (8 x + 5)

= 2 (8 x + 5) \frac{d}{d x} (8 x + 5)

\frac{d}{d x} (8 x + 5) = 8

= 2 (8 x + 5) \cdot 8

Simplify

= 16 (8 x + 5)

\frac{8}{7 x ^{2}}

(5 x^{6} + 8 x^{3})^{4}

\frac{2}{s ( 0.12 s + 1 )}

x y^{^{'}} = y + 7 x^{2} sin (x)

\frac{\partial}{\partial x} (x y^{\frac{1}{2}})

What is the derivative of (8x+5^2) ?
The derivative of (8x+5^2) is 16(8x+5)
What is the first derivative of (8x+5^2) ?
The first derivative of (8x+5^2) is 16(8x+5)