What is the derivative of arccos(6x) ?

The derivative of arccos(6x) is -6/(sqrt(1-36x^2))

What is the first derivative of arccos(6x) ?

The first derivative of arccos(6x) is -6/(sqrt(1-36x^2))

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\frac{d}{d x} (arccos (6 x))

- \frac{6}{1 - 36 x ^{2}}

Solution steps

\frac{d}{d x} (arccos (6 x))

Apply the chain rule:

- \frac{1}{1 - ( 6 x ) ^{2}} \frac{d}{d x} (6 x)

= - \frac{1}{1 - ( 6 x ) ^{2}} \frac{d}{d x} (6 x)

\frac{d}{d x} (6 x) = 6

= - \frac{1}{1 - ( 6 x ) ^{2}} \cdot 6

Simplify

- \frac{1}{1 - ( 6 x ) ^{2}} \cdot 6 : - \frac{6}{1 - 36 x ^{2}}

= - \frac{6}{1 - 36 x ^{2}}

\int x^{3} \cdot ln (x) d x

\int_{1}^{e} \frac{9 x ^{2} + 9 x + 9}{x} d x

\int \frac{1}{6} d x

\frac{\partial}{\partial x} (6 x^{2} - 4 x y^{2})

f (- 1) = \frac{x + 3}{2}

What is the derivative of arccos(6x) ?
The derivative of arccos(6x) is -6/(sqrt(1-36x^2))
What is the first derivative of arccos(6x) ?
The first derivative of arccos(6x) is -6/(sqrt(1-36x^2))