What is the derivative of ((3-x))/(4x) ?

The derivative of ((3-x))/(4x) is -3/(4x^2)

What is the first derivative of ((3-x))/(4x) ?

The first derivative of ((3-x))/(4x) is -3/(4x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{( 3 - x )}{4 x}

- \frac{3}{4 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 - x}{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (\frac{3 - x}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{4} \cdot \frac{\frac{d}{d x} ( 3 - x ) x - \frac{d x}{d x} ( 3 - x )}{x ^{2}}

\frac{d}{d x} (3 - x) = - 1

\frac{d x}{d x} = 1

= \frac{1}{4} \cdot \frac{( - 1 ) x - 1 \cdot ( 3 - x )}{x ^{2}}

Simplify

\frac{1}{4} \cdot \frac{( - 1 ) x - 1 \cdot ( 3 - x )}{x ^{2}} : - \frac{3}{4 x ^{2}}

= - \frac{3}{4 x ^{2}}

\int cos^{4} (3 - x) sin (3 - x) d x

y = x, y = 1 - x^{2}, - 1, 2

- \frac{39}{( 8 x + 5 ) ^{2}}, at x = 2

\int_{0}^{4} \frac{12}{x ^{2} + 5 x + 6} d x

\int \frac{4}{x ^{2} + 8 x} d x

What is the derivative of ((3-x))/(4x) ?
The derivative of ((3-x))/(4x) is -3/(4x^2)
What is the first derivative of ((3-x))/(4x) ?
The first derivative of ((3-x))/(4x) is -3/(4x^2)