What is the derivative of (x^4/8) ?

The derivative of (x^4/8) is (x^3)/2

What is the first derivative of (x^4/8) ?

The first derivative of (x^4/8) is (x^3)/2

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\frac{d}{d x} (\frac{x ^{4}}{8})

\frac{x ^{3}}{2}

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (x^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} \cdot 4 x^{4 - 1}

Simplify

\frac{1}{8} \cdot 4 x^{4 - 1} : \frac{x ^{3}}{2}

= \frac{x ^{3}}{2}

\frac{\partial}{\partial x} (e^{4 (e^{x} - 1)})

x \to 0 lim ((1 - 6 x)^{\frac{6}{x}})

\frac{\partial}{\partial y} (3 x^{4} y^{2} + 3)

y^{3} y^{^{'}} + x^{3} = 0

x^{2} + 2 x

What is the derivative of (x^4/8) ?
The derivative of (x^4/8) is (x^3)/2
What is the first derivative of (x^4/8) ?
The first derivative of (x^4/8) is (x^3)/2