What is laplacetransform 2sin^2(t) ?

The answer to laplacetransform 2sin^2(t) is 4/(s(s^2+4))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 2sin^2(t)

laplace transform

2 sin^{2} (t)

\frac{4}{s ( s ^{2} + 4 )}

Solution steps

L {2 sin^{2} (t)}

Rewrite using trig identities

L {1 - cos (2 t)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {1} - L {cos (2 t)}

L {1} : \frac{1}{s}

L {cos (2 t)} : \frac{s}{s ^{2} + 4}

= \frac{1}{s} - \frac{s}{s ^{2} + 4}

Simplify

\frac{1}{s} - \frac{s}{s ^{2} + 4} : \frac{4}{s ( s ^{2} + 4 )}

= \frac{4}{s ( s ^{2} + 4 )}

\frac{d}{d x} (\frac{x ^{2}}{( 1 + 2 tan ( x ) )})

4 cos (3 t)

x \to 0 lim (96)

\int 9 t e^{t} d t

\frac{d}{d x} ([x + (x + sin^{2} (x))^{3}]^{4})

What is laplacetransform 2sin^2(t) ?
The answer to laplacetransform 2sin^2(t) is 4/(s(s^2+4))