What is the derivative of [x+(x+sin^2(x)^3]^4) ?

The derivative of [x+(x+sin^2(x)^3]^4) is 4(x+(x+sin^2(x))^3)^3(1+3(x+sin^2(x))^2(1+sin(2x)))

What is the first derivative of [x+(x+sin^2(x)^3]^4) ?

The first derivative of [x+(x+sin^2(x)^3]^4) is 4(x+(x+sin^2(x))^3)^3(1+3(x+sin^2(x))^2(1+sin(2x)))

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\frac{d}{d x} ([x + (x + sin^{2} (x))^{3}]^{4})

4 (x + (x + sin^{2} (x))^{3})^{3} (1 + 3 (x + sin^{2} (x))^{2} (1 + sin (2 x)))

Solution steps

\frac{d}{d x} ((x + (x + sin^{2} (x))^{3})^{4})

Apply the chain rule:

4 (x + (x + sin^{2} (x))^{3})^{3} \frac{d}{d x} (x + (x + sin^{2} (x))^{3})

= 4 (x + (x + sin^{2} (x))^{3})^{3} \frac{d}{d x} (x + (x + sin^{2} (x))^{3})

\frac{d}{d x} (x + (x + sin^{2} (x))^{3}) = 1 + 3 (x + sin^{2} (x))^{2} (1 + sin (2 x))

= 4 (x + (x + sin^{2} (x))^{3})^{3} (1 + 3 (x + sin^{2} (x))^{2} (1 + sin (2 x)))

\int 15 x x + 1 d x

n = 2 \sum \infty \frac{1}{n ^{3} - n}

y = ln (x^{13})

\int \frac{x ^{2} - 3 x - 1}{x ( x ^{2} + 4 )} d x

x^{- 2}

What is the derivative of [x+(x+sin^2(x)^3]^4) ?
The derivative of [x+(x+sin^2(x)^3]^4) is 4(x+(x+sin^2(x))^3)^3(1+3(x+sin^2(x))^2(1+sin(2x)))
What is the first derivative of [x+(x+sin^2(x)^3]^4) ?
The first derivative of [x+(x+sin^2(x)^3]^4) is 4(x+(x+sin^2(x))^3)^3(1+3(x+sin^2(x))^2(1+sin(2x)))