What is the tangent of f(x)= 1/(sqrt(1x)),\at x=9 ?

The tangent of f(x)= 1/(sqrt(1x)),\at x=9 is y=-1/54 x+1/2

Popular >

tangent of f(x)= 1/(sqrt(1x)),\at x=9

tangent of

f (x) = \frac{1}{1 x}, at x = 9

y = - \frac{1}{54} x + \frac{1}{2}

Solution steps

Find the tangent point:

(9, \frac{1}{3})

Find the slope of

f (x) = \frac{1}{1 x} : \frac{df ( x )}{d x} = - \frac{1}{2 x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{54}

Find the line with slope m=

- \frac{1}{54}

and passing through

(9, \frac{1}{3}) : y = - \frac{1}{54} x + \frac{1}{2}

y = - \frac{1}{54} x + \frac{1}{2}

x \to 4 lim (\frac{2 x + 3}{9 x + 7})

\int_{0}^{1} \frac{1}{x ^{2} - 3 x + 2} d x

\int_{- 2}^{4} (10 + 4 x - 3 x^{3}) d x

f (x) = x^{3} - 3 x + 1, at x = 3

\frac{3}{( 2 x + 3 ) ^{2}}

What is the tangent of f(x)= 1/(sqrt(1x)),\at x=9 ?
The tangent of f(x)= 1/(sqrt(1x)),\at x=9 is y=-1/54 x+1/2