What is the integral of (8/(sqrt(x))) ?

The integral of (8/(sqrt(x))) is 16sqrt(x)+C

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integral of (8/(sqrt(x)))

\int (\frac{8}{x}) d x

16 x + C

Solution steps

\int \frac{8}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 8 \cdot 2 x^{\frac{1}{2}}

Simplify

8 \cdot 2 x^{\frac{1}{2}} : 16 x

= 16 x

Add a constant to the solution

= 16 x + C

x \to 3 - lim (f (x))

- x^{2}, 3 x - 10, x = 0

\frac{e ^{x}}{8 x ^{2}}

\int \frac{10}{x ^{9}} d x

f (x) = x^{4} - 1 3^{2} + 36, at x = - 2

What is the integral of (8/(sqrt(x))) ?
The integral of (8/(sqrt(x))) is 16sqrt(x)+C