What is the solution for 4x^2(dy)/(dx)=(dy)/(dx)+9xe^{-y} ?

The solution for 4x^2(dy)/(dx)=(dy)/(dx)+9xe^{-y} is y=ln(9/8 ln(4x^2-1)+c_{1})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2(dy)/(dx)=(dy)/(dx)+9xe^{-y}

4 x^{2} \frac{d y}{d x} = \frac{d y}{d x} + 9 x e^{- y}

y = ln (\frac{9}{8} ln (4 x^{2} - 1) + c_{1})

Solution steps

4 x^{2} \frac{d y}{d x} = \frac{d y}{d x} + 9 x e^{- y}

Solve separable ODE:

y = ln (\frac{9}{8} ln (4 x^{2} - 1) + c_{1})

y = ln (\frac{9}{8} ln (4 x^{2} - 1) + c_{1})

x^{2} - 2 x + 3

f (x) = \frac{3 x}{x ^{2} - 6}, 3, at x = 3

\frac{8 5}{15} x^{\frac{3}{2}} - 2

\int cos^{3} (7 x) sin^{- 2} (7 x) d x

x^{^{'}} = - x

What is the solution for 4x^2(dy)/(dx)=(dy)/(dx)+9xe^{-y} ?
The solution for 4x^2(dy)/(dx)=(dy)/(dx)+9xe^{-y} is y=ln(9/8 ln(4x^2-1)+c_{1})