What is area y=sqrt(x),y=-x+2,[0,2] ?

The answer to area y=sqrt(x),y=-x+2,[0,2] is (4sqrt(2)-1)/3

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area y=sqrt(x),y=-x+2,[0,2]

area

y = x, y = - x + 2, [0, 2]

\frac{4 2 - 1}{3}

Decimal

1.55228 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x - (- x + 2) d x

Solve

\int_{0}^{2} x - (- x + 2) d x : \frac{4 2 - 1}{3}

The area is:

= \frac{4 2 - 1}{3}

x + y = 13, x + 7 = y^{2}

f (x) = \frac{x ^{2} + 4 x}{5}

x \to 0 - lim (\frac{11 x}{∣ x ∣})

\frac{d}{d x} (100 - ln (2 x + 1))

x \to 0 lim (+ (\frac{1}{x}))

What is area y=sqrt(x),y=-x+2,[0,2] ?
The answer to area y=sqrt(x),y=-x+2,[0,2] is (4sqrt(2)-1)/3