What is the sum from n=4 to infinity}(\sqrt{n of)/(n-3) ?

The sum from n=4 to infinity}(\sqrt{n of)/(n-3) is diverges

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sum from n=4 to infinity}(\sqrt{n of)/(n-3)

n = 4 \sum \infty \frac{n}{n - 3}

diverges

Solution steps

n = 4 \sum \infty \frac{n}{n - 3}

Apply Series Comparison Test:

diverges

= diverges

\frac{d y}{d x} - e^{2 x + y} = 0

\frac{d}{d x} (a x^{3} + b x^{2} + c x)

\int \frac{( x ^{3} + 3 )}{x ^{2}} d x

\frac{\partial ^{2}}{\partial x \partial y} (x^{2} - e^{y^{2}})

\int_{0}^{y^{3}} x e^{\frac{- x}{y}} d x

What is the sum from n=4 to infinity}(\sqrt{n of)/(n-3) ?
The sum from n=4 to infinity}(\sqrt{n of)/(n-3) is diverges