What is the derivative of 2x^{2/3} ?

The derivative of 2x^{2/3} is 4/(3x^{1/3)}

What is the first derivative of 2x^{2/3} ?

The first derivative of 2x^{2/3} is 4/(3x^{1/3)}

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\frac{d}{d x} (2 x^{\frac{2}{3}})

\frac{4}{3 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (2 x^{\frac{2}{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{\frac{2}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot \frac{2}{3} x^{\frac{2}{3} - 1}

Simplify

2 \cdot \frac{2}{3} x^{\frac{2}{3} - 1} : \frac{4}{3 x ^{\frac{1}{3}}}

= \frac{4}{3 x ^{\frac{1}{3}}}

2 + 3 x

\frac{d}{d x} (- 9 sin (3 x))

\frac{d}{d x} (tan (π - \frac{9}{x}))

\frac{d}{d x} (9 x^{9} e^{x - 1})

\int \frac{5}{x ln ( 3 x )} d x

What is the derivative of 2x^{2/3} ?
The derivative of 2x^{2/3} is 4/(3x^{1/3)}
What is the first derivative of 2x^{2/3} ?
The first derivative of 2x^{2/3} is 4/(3x^{1/3)}