What is (\partial)/(\partial x)(4sin(4x)) ?

The answer to (\partial)/(\partial x)(4sin(4x)) is 16cos(4x)

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(\partial)/(\partial x)(4sin(4x))

\frac{\partial}{\partial x} (4 sin (4 x))

16 cos (4 x)

Solution steps

\frac{\partial}{\partial x} (4 sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{\partial}{\partial x} (4 x)

= cos (4 x) \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x) = 4

= 4 cos (4 x) \cdot 4

Simplify

= 16 cos (4 x)

\frac{d}{d x} (arccos (x + y))

f (x) = 3 x^{2}, at x = (6)

x \to 1 + lim (\frac{1}{x ^{3} - 1})

f (x) = tan^{3} (x)

\int_{1}^{e^{4}} x^{3} ln (x) d x

What is (\partial)/(\partial x)(4sin(4x)) ?
The answer to (\partial)/(\partial x)(4sin(4x)) is 16cos(4x)