What is the derivative of (-2x+1^3) ?

The derivative of (-2x+1^3) is -6(-2x+1)^2

What is the first derivative of (-2x+1^3) ?

The first derivative of (-2x+1^3) is -6(-2x+1)^2

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\frac{d}{d x} ((- 2 x + 1)^{3})

- 6 (- 2 x + 1)^{2}

Solution steps

\frac{d}{d x} ((- 2 x + 1)^{3})

Apply the chain rule:

3 (- 2 x + 1)^{2} \frac{d}{d x} (- 2 x + 1)

= 3 (- 2 x + 1)^{2} \frac{d}{d x} (- 2 x + 1)

\frac{d}{d x} (- 2 x + 1) = - 2

= 3 (- 2 x + 1)^{2} (- 2)

Simplify

= - 6 (- 2 x + 1)^{2}

\int \frac{3 x}{2 x} d x

\int \frac{1 - cos ( x )}{2} d x

\frac{\partial}{\partial t} (e^{- 2 t} cos (x))

x \to 0 lim (sin (\frac{7}{x}))

f (x) = \frac{9}{x}, at x = 1

What is the derivative of (-2x+1^3) ?
The derivative of (-2x+1^3) is -6(-2x+1)^2
What is the first derivative of (-2x+1^3) ?
The first derivative of (-2x+1^3) is -6(-2x+1)^2