What is the integral of (5-50x)/(sqrt(1-25x^2)) ?

The integral of (5-50x)/(sqrt(1-25x^2)) is arcsin(5x)+2sqrt(1-25x^2)+C

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integral of (5-50x)/(sqrt(1-25x^2))

\int \frac{5 - 50 x}{1 - 25 x ^{2}} d x

arcsin (5 x) + 2 1 - 25 x^{2} + C

Solution steps

\int \frac{5 - 50 x}{1 - 25 x ^{2}} d x

Expand

\frac{5 - 50 x}{1 - 25 x ^{2}} : \frac{5}{1 - 25 x ^{2}} - \frac{50 x}{1 - 25 x ^{2}}

= \int \frac{5}{1 - 25 x ^{2}} - \frac{50 x}{1 - 25 x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{5}{1 - 25 x ^{2}} d x - \int \frac{50 x}{1 - 25 x ^{2}} d x

\int \frac{5}{1 - 25 x ^{2}} d x = arcsin (5 x)

\int \frac{50 x}{1 - 25 x ^{2}} d x = - 2 1 - 25 x^{2}

= arcsin (5 x) - (- 2 1 - 25 x^{2})

Simplify

= arcsin (5 x) + 2 1 - 25 x^{2}

Add a constant to the solution

= arcsin (5 x) + 2 1 - 25 x^{2} + C

n = 0 \sum \infty 2 \cdot 6^{n}

x^{2} sin (5 x)

\frac{d y}{d x} = \frac{( x - 4 )}{y + 5}

\frac{t}{2 t + 3}

\int cos^{3} (4 θ) sin (4 θ) d θ

What is the integral of (5-50x)/(sqrt(1-25x^2)) ?
The integral of (5-50x)/(sqrt(1-25x^2)) is arcsin(5x)+2sqrt(1-25x^2)+C