What is the solution for (dy)/(dx)=((x-4))/(y+5) ?

The solution for (dy)/(dx)=((x-4))/(y+5) is y=-5+sqrt(x^2-8x+c_{1)+25},y=-sqrt(x^2-8x+c_{1)+25}-5

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(dy)/(dx)=((x-4))/(y+5)

\frac{d y}{d x} = \frac{( x - 4 )}{y + 5}

y = - 5 + x^{2} - 8 x + c_{1} + 25, y = - x^{2} - 8 x + c_{1} + 25 - 5

Solution steps

\frac{d y}{d x} = \frac{( x - 4 )}{y + 5}

Solve separable ODE:

y = - 5 + x^{2} - 8 x + c_{1} + 25, y = - x^{2} - 8 x + c_{1} + 25 - 5

y = - 5 + x^{2} - 8 x + c_{1} + 25, y = - x^{2} - 8 x + c_{1} + 25 - 5

\frac{t}{2 t + 3}

\int cos^{3} (4 θ) sin (4 θ) d θ

\frac{d y}{d x} = - x e^{- x + y}

y^{^{'}} = y (2 + y) t

\int \frac{1}{x x ^{2} + 1} d x

What is the solution for (dy)/(dx)=((x-4))/(y+5) ?
The solution for (dy)/(dx)=((x-4))/(y+5) is y=-5+sqrt(x^2-8x+c_{1)+25},y=-sqrt(x^2-8x+c_{1)+25}-5