What is the solution for (dy)/(dx)=-xe^{-x+y} ?

The solution for (dy)/(dx)=-xe^{-x+y} is y=-ln(-e^{-x}x-e^{-x}-c_{1})

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(dy)/(dx)=-xe^{-x+y}

\frac{d y}{d x} = - x e^{- x + y}

y = - ln (- e^{- x} x - e^{- x} - c_{1})

Solution steps

\frac{d y}{d x} = - x e^{- x + y}

Solve separable ODE:

y = - ln (- e^{- x} x - e^{- x} - c_{1})

y = - ln (- e^{- x} x - e^{- x} - c_{1})

y^{^{'}} = y (2 + y) t

\int \frac{1}{x x ^{2} + 1} d x

\frac{d}{d x} (ln (2 x - 4))

\int_{0}^{1} (\frac{1}{1 + x ^{2}}) d x

x \to 6 lim (4)

What is the solution for (dy)/(dx)=-xe^{-x+y} ?
The solution for (dy)/(dx)=-xe^{-x+y} is y=-ln(-e^{-x}x-e^{-x}-c_{1})