What is the derivative of ln(2x-4) ?

The derivative of ln(2x-4) is 1/(x-2)

What is the first derivative of ln(2x-4) ?

The first derivative of ln(2x-4) is 1/(x-2)

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\frac{d}{d x} (ln (2 x - 4))

\frac{1}{x - 2}

Solution steps

\frac{d}{d x} (ln (2 x - 4))

Apply the chain rule:

\frac{1}{2 x - 4} \frac{d}{d x} (2 x - 4)

= \frac{1}{2 x - 4} \frac{d}{d x} (2 x - 4)

\frac{d}{d x} (2 x - 4) = 2

= \frac{1}{2 x - 4} \cdot 2

Simplify

\frac{1}{2 x - 4} \cdot 2 : \frac{1}{x - 2}

= \frac{1}{x - 2}

\int_{0}^{1} (\frac{1}{1 + x ^{2}}) d x

x \to 6 lim (4)

\int 3 x^{2} x^{3} + 1 d x

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\frac{d}{d x} (e^{- 2 x} \cdot cos (x))

What is the derivative of ln(2x-4) ?
The derivative of ln(2x-4) is 1/(x-2)
What is the first derivative of ln(2x-4) ?
The first derivative of ln(2x-4) is 1/(x-2)