What is the derivative of f(x)=x^3-2x+1 ?

The derivative of f(x)=x^3-2x+1 is 3x^2-2

What is the first derivative of f(x)=x^3-2x+1 ?

The first derivative of f(x)=x^3-2x+1 is 3x^2-2

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derivative of

f (x) = x^{3} - 2 x + 1

3 x^{2} - 2

Solution steps

\frac{d}{d x} (x^{3} - 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 3 x^{2} - 2 + 0

Simplify

= 3 x^{2} - 2

- 3 sin (2 t)

\int x^{\frac{3}{2}} + 2 x + 1 d x

x y^{^{'}} + y = 32 x

\int ∣ x - 4 ∣ d x

\frac{d}{d x} (x^{3} - 5 x + 3)

What is the derivative of f(x)=x^3-2x+1 ?
The derivative of f(x)=x^3-2x+1 is 3x^2-2
What is the first derivative of f(x)=x^3-2x+1 ?
The first derivative of f(x)=x^3-2x+1 is 3x^2-2