What is the solution for x^2(dy)/(dx)+3xy=ln(x) ?

The solution for x^2(dy)/(dx)+3xy=ln(x) is y=(ln(x))/(2x)-1/(4x)+(c_{1})/(x^3)

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x^2(dy)/(dx)+3xy=ln(x)

x^{2} \frac{d y}{d x} + 3 x y = ln (x)

y = \frac{ln ( x )}{2 x} - \frac{1}{4 x} + \frac{c _{1}}{x ^{3}}

Solution steps

x^{2} \frac{d y}{d x} + 3 x y = ln (x)

Solve linear ODE:

y = \frac{ln ( x )}{2 x} - \frac{1}{4 x} + \frac{c _{1}}{x ^{3}}

y = \frac{ln ( x )}{2 x} - \frac{1}{4 x} + \frac{c _{1}}{x ^{3}}

x y = cot (x y)

\int \frac{x}{( z ^{2} + x ^{2} ) ^{\frac{3}{2}}} d x

y = \frac{3}{x}

\int (6) d x

\frac{\partial}{\partial t} (3 s^{2} + t^{2})

What is the solution for x^2(dy)/(dx)+3xy=ln(x) ?
The solution for x^2(dy)/(dx)+3xy=ln(x) is y=(ln(x))/(2x)-1/(4x)+(c_{1})/(x^3)