What is the derivative of y= 3/x ?

The derivative of y= 3/x is -3/(x^2)

What is the first derivative of y= 3/x ?

The first derivative of y= 3/x is -3/(x^2)

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derivative of

y = \frac{3}{x}

- \frac{3}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 1 \cdot x^{- 1 - 1})

Simplify

3 (- 1 \cdot x^{- 1 - 1}) : - \frac{3}{x ^{2}}

= - \frac{3}{x ^{2}}

\int (6) d x

\frac{\partial}{\partial t} (3 s^{2} + t^{2})

\int_{0}^{3} x e^{\frac{x}{2}} d x

\int 0.06 e^{0.01 x} d x

\int \frac{2 x + 1}{x} d x

What is the derivative of y= 3/x ?
The derivative of y= 3/x is -3/(x^2)
What is the first derivative of y= 3/x ?
The first derivative of y= 3/x is -3/(x^2)