What is area x/(1+x^2),((x^2))/(1+x^3) ?

The answer to area x/(1+x^2),((x^2))/(1+x^3) is 1/6 ln(2)

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area x/(1+x^2),((x^2))/(1+x^3)

area

\frac{x}{1 + x ^{2}}, \frac{( x ^{2} )}{1 + x ^{3}}

\frac{1}{6} ln (2)

Decimal Notation

0.11552 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} \frac{x}{1 + x ^{2}} - \frac{x ^{2}}{1 + x ^{3}} d x

Solve

\int_{0}^{1} \frac{x}{1 + x ^{2}} - \frac{x ^{2}}{1 + x ^{3}} d x : \frac{1}{6} ln (2)

The area is:

= \frac{1}{6} ln (2)

y^{^{'}} = \frac{x y + 2 y}{x + 3}

x (x^{3} + 1) y^{^{'}} + (2 x^{3} - 1) y = \frac{x ^{3} - 2}{x}

\int x^{2} - 49 d x

y^{^{''}} + 2 y^{^{'}} + 2 = 0

\frac{\partial}{\partial x} (sin (x y^{2}) e^{2 x - 3 y})

What is area x/(1+x^2),((x^2))/(1+x^3) ?
The answer to area x/(1+x^2),((x^2))/(1+x^3) is 1/6 ln(2)