What is area x=-5,x=1,y=3x,y=x^2-4 ?

The answer to area x=-5,x=1,y=3x,y=x^2-4 is 206/3

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area x=-5,x=1,y=3x,y=x^2-4

area

x = - 5, x = 1, y = 3 x, y = x^{2} - 4

\frac{206}{3}

Decimal Notation

68.66666 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{1} 3 x - (x^{2} - 4) d x

Solve

\int_{- 5}^{1} 3 x - (x^{2} - 4) d x : \frac{206}{3}

The area is:

= \frac{206}{3}

\frac{d}{d x} (\frac{4 x - 7}{2 x + 1})

\int \frac{6 x ^{2} - 5 x + 3}{x} d x

\frac{\partial}{\partial x} (3 x y e^{y - x})

(3, 3), (2, - 5)

(x^{2} - 5) y y^{^{'}} = 2 x

What is area x=-5,x=1,y=3x,y=x^2-4 ?
The answer to area x=-5,x=1,y=3x,y=x^2-4 is 206/3