What is the derivative of (4x-7/(2x+1)) ?

The derivative of (4x-7/(2x+1)) is (18)/((2x+1)^2)

What is the first derivative of (4x-7/(2x+1)) ?

The first derivative of (4x-7/(2x+1)) is (18)/((2x+1)^2)

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\frac{d}{d x} (\frac{4 x - 7}{2 x + 1})

\frac{18}{( 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x - 7}{2 x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x - 7 ) ( 2 x + 1 ) - \frac{d}{d x} ( 2 x + 1 ) ( 4 x - 7 )}{( 2 x + 1 ) ^{2}}

\frac{d}{d x} (4 x - 7) = 4

\frac{d}{d x} (2 x + 1) = 2

= \frac{4 ( 2 x + 1 ) - 2 ( 4 x - 7 )}{( 2 x + 1 ) ^{2}}

Expand

4 (2 x + 1) - 2 (4 x - 7) : 18

= \frac{18}{( 2 x + 1 ) ^{2}}

\int \frac{6 x ^{2} - 5 x + 3}{x} d x

\frac{\partial}{\partial x} (3 x y e^{y - x})

(3, 3), (2, - 5)

(x^{2} - 5) y y^{^{'}} = 2 x

\int \frac{x}{3} \cdot sin (x^{2}) d x

What is the derivative of (4x-7/(2x+1)) ?
The derivative of (4x-7/(2x+1)) is (18)/((2x+1)^2)
What is the first derivative of (4x-7/(2x+1)) ?
The first derivative of (4x-7/(2x+1)) is (18)/((2x+1)^2)