What is implicit (dy)/(dx),y^3-2xy+7=3x+1 ?

The answer to implicit (dy)/(dx),y^3-2xy+7=3x+1 is (dy)/(dx)=(3+2y)/(3y^2-2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

implicit (dy)/(dx),y^3-2xy+7=3x+1

implicit derivative

\frac{d y}{d x}, y^{3} - 2 x y + 7 = 3 x + 1

\frac{d y}{d x} = \frac{3 + 2 y}{3 y ^{2} - 2 x}

Solution steps

y^{3} - 2 x y + 7 = 3 x + 1

Treat

y

y (x)

Differentiate both sides:

3 y^{2} \frac{d y}{d x} - 2 (x \frac{d y}{d x} + y) = 3

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{3 + 2 y}{3 y ^{2} - 2 x}

\frac{d y}{d x} = \frac{3 + 2 y}{3 y ^{2} - 2 x}

\int 5 x \cdot cos (8 x) d x

\frac{d}{d x} (- sin^{2} (x))

\frac{\partial}{\partial y} (2 ln (y))

\int \frac{1}{9 x - 5} d x

What is implicit (dy)/(dx),y^3-2xy+7=3x+1 ?
The answer to implicit (dy)/(dx),y^3-2xy+7=3x+1 is (dy)/(dx)=(3+2y)/(3y^2-2x)