What is (\partial)/(\partial y)(2ln(y)) ?

The answer to (\partial)/(\partial y)(2ln(y)) is 2/y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(2ln(y))

\frac{\partial}{\partial y} (2 ln (y))

\frac{2}{y}

Solution steps

\frac{\partial}{\partial y} (2 ln (y))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial y} (ln (y))

Apply the common derivative:

\frac{\partial}{\partial y} (ln (y)) = \frac{1}{y}

= 2 \cdot \frac{1}{y}

Simplify

2 \cdot \frac{1}{y} : \frac{2}{y}

= \frac{2}{y}

\int \frac{1}{9 x - 5} d x

sin (7 x) - cos (4 x)

h (x) = \frac{1}{x ^{5}}

\frac{\partial}{\partial x} (π x x^{2} + h^{2})

\int \frac{( e ^{x} - e ^{- x} )}{2} d x

What is (\partial)/(\partial y)(2ln(y)) ?
The answer to (\partial)/(\partial y)(2ln(y)) is 2/y