What is the tangent of f(x)=2sin(x),\at x= pi/6 ?

The tangent of f(x)=2sin(x),\at x= pi/6 is y=sqrt(3)x+1-pi/(2sqrt(3))

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tangent of f(x)=2sin(x),\at x= pi/6

tangent of

f (x) = 2 sin (x), at x = \frac{π}{6}

y = 3 x + 1 - \frac{π}{2 3}

Solution steps

Find the tangent point:

(\frac{π}{6}, 1)

Find the slope of

f (x) = 2 sin (x) : \frac{df ( x )}{d x} = 2 cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(\frac{π}{6}, 1) : y = 3 x + 1 - \frac{π}{2 3}

y = 3 x + 1 - \frac{π}{2 3}

y = x, y = \frac{1}{2} x, x = 9

\int cos^{3} (\frac{x}{14}) d x

\frac{\partial}{\partial x} (e^{5 x yz - 6})

\int 1 + 3 x^{2} y^{2} d y

\frac{d}{d x} (- 12)

What is the tangent of f(x)=2sin(x),\at x= pi/6 ?
The tangent of f(x)=2sin(x),\at x= pi/6 is y=sqrt(3)x+1-pi/(2sqrt(3))