What is the d/(dt)(3cos(2t)) ?

The d/(dt)(3cos(2t)) is -6sin(2t)

What is the first d/(dt)(3cos(2t)) ?

The first d/(dt)(3cos(2t)) is -6sin(2t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (3 cos (2 t))

- 6 sin (2 t)

Solution steps

\frac{d}{d t} (3 cos (2 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (cos (2 t))

Apply the chain rule:

- sin (2 t) \frac{d}{d t} (2 t)

= - sin (2 t) \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= 3 (- sin (2 t) \cdot 2)

Simplify

= - 6 sin (2 t)

\int \frac{x ^{3} - ( x - 1 ) ^{2}}{x} d x

x \to 1 lim (4 x - 1)

\frac{d}{d x} (100 x^{2} - 26 x e^{x})

\frac{d}{d x} (lo g_{10} (3 x + 4))

\frac{\partial}{\partial x} (tan (x y) + y e^{3 x})