What is the integral from 0 to 1 of 1/(x^{0.5)} ?

The integral from 0 to 1 of 1/(x^{0.5)} is 2

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integral from 0 to 1 of 1/(x^{0.5)}

\int_{0}^{1} \frac{1}{x ^{0.5}} d x

2

Solution steps

\int_{0}^{1} \frac{1}{x ^{0.5}} d x

Apply the Power Rule

: [2 x^{0.5}]_{0}^{1}

= [2 x^{0.5}]_{0}^{1}

Apply radical rule:

= [2 x]_{0}^{1}

Compute the boundaries:

2

= 2

\frac{\partial}{\partial x} ((3 x + 1) y)

\int \frac{( x ^{2} + 1 )}{( x - 4 ) ( x - 3 ) ^{2}} d x

y^{^{''}} - 10 y^{^{'}} + 34 y = 0, y (0) = - 2, y^{^{'}} (0) = - 3

\frac{3}{x}, \frac{3}{x ^{2}}, 6

y = 5, y = x^{2} + 1

What is the integral from 0 to 1 of 1/(x^{0.5)} ?
The integral from 0 to 1 of 1/(x^{0.5)} is 2