What is the integral of sec^2(θ)+6 ?

The integral of sec^2(θ)+6 is tan(θ)+6θ+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sec^2(θ)+6

\int sec^{2} (θ) + 6 d θ

tan (θ) + 6 θ + C

Solution steps

\int sec^{2} (θ) + 6 d θ

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (θ) d θ + \int 6 d θ

\int sec^{2} (θ) d θ = tan (θ)

\int 6 d θ = 6 θ

= tan (θ) + 6 θ

Add a constant to the solution

= tan (θ) + 6 θ + C

\frac{x ^{2}}{1 + x}

\frac{d}{d r} (ln (r))

f (x) = ln (6 - x^{2} + 2 x^{4})

\int t^{3} (1 + t^{4})^{3} d t