What is area y=6e^x,y=6e^{-x},x=1 ?

The answer to area y=6e^x,y=6e^{-x},x=1 is 6e+6/e-12

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area y=6e^x,y=6e^{-x},x=1

area

y = 6 e^{x}, y = 6 e^{- x}, x = 1

6 e + \frac{6}{e} - 12

Decimal Notation

6.51696 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} 6 e^{x} - 6 e^{- x} d x

Solve

\int_{0}^{1} 6 e^{x} - 6 e^{- x} d x : 6 e + \frac{6}{e} - 12

The area is:

= 6 e + \frac{6}{e} - 12

\int \frac{1}{y ^{2} - 9} d y

\int \frac{1}{9 - 64 x ^{2}} d x

y (θ) = π^{4} cos (θ)

\frac{d}{d t} (9 + t)

\frac{d}{d x} (x + 2 cos (x))

What is area y=6e^x,y=6e^{-x},x=1 ?
The answer to area y=6e^x,y=6e^{-x},x=1 is 6e+6/e-12