What is the d/(dt)(sqrt(9+t)) ?

The d/(dt)(sqrt(9+t)) is 1/(2sqrt(9+t))

What is the first d/(dt)(sqrt(9+t)) ?

The first d/(dt)(sqrt(9+t)) is 1/(2sqrt(9+t))

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\frac{d}{d t} (9 + t)

\frac{1}{2 9 + t}

Solution steps

\frac{d}{d t} (9 + t)

Apply the chain rule:

\frac{1}{2 9 + t} \frac{d}{d t} (9 + t)

= \frac{1}{2 9 + t} \frac{d}{d t} (9 + t)

\frac{d}{d t} (9 + t) = 1

= \frac{1}{2 9 + t} \cdot 1

Simplify

= \frac{1}{2 9 + t}

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What is the d/(dt)(sqrt(9+t)) ?
The d/(dt)(sqrt(9+t)) is 1/(2sqrt(9+t))
What is the first d/(dt)(sqrt(9+t)) ?
The first d/(dt)(sqrt(9+t)) is 1/(2sqrt(9+t))