What is the derivative of f(x)=(2x-9)^4(x^2+x+1)^5 ?

The derivative of f(x)=(2x-9)^4(x^2+x+1)^5 is 8(2x-9)^3(x^2+x+1)^5+5(x^2+x+1)^4(2x+1)(2x-9)^4

What is the first derivative of f(x)=(2x-9)^4(x^2+x+1)^5 ?

The first derivative of f(x)=(2x-9)^4(x^2+x+1)^5 is 8(2x-9)^3(x^2+x+1)^5+5(x^2+x+1)^4(2x+1)(2x-9)^4

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derivative of

f (x) = (2 x - 9)^{4} (x^{2} + x + 1)^{5}

8 (2 x - 9)^{3} (x^{2} + x + 1)^{5} + 5 (x^{2} + x + 1)^{4} (2 x + 1) (2 x - 9)^{4}

Solution steps

\frac{d}{d x} ((2 x - 9)^{4} (x^{2} + x + 1)^{5})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (2 x - 9)^{4}, g = (x^{2} + x + 1)^{5}

= \frac{d}{d x} ((2 x - 9)^{4}) (x^{2} + x + 1)^{5} + \frac{d}{d x} ((x^{2} + x + 1)^{5}) (2 x - 9)^{4}

\frac{d}{d x} ((2 x - 9)^{4}) = 8 (2 x - 9)^{3}

\frac{d}{d x} ((x^{2} + x + 1)^{5}) = 5 (x^{2} + x + 1)^{4} (2 x + 1)

= 8 (2 x - 9)^{3} (x^{2} + x + 1)^{5} + 5 (x^{2} + x + 1)^{4} (2 x + 1) (2 x - 9)^{4}

y = x^{2} - 2 x, (5, 15)

\frac{1}{( s + 2 ) ^{2}}

\int \frac{sin ( x )}{cos ( x ) + 1} d x

(y - y x^{2}) \frac{d y}{d x} = (y + 1)^{2}

f (x) = 24

What is the derivative of f(x)=(2x-9)^4(x^2+x+1)^5 ?
The derivative of f(x)=(2x-9)^4(x^2+x+1)^5 is 8(2x-9)^3(x^2+x+1)^5+5(x^2+x+1)^4(2x+1)(2x-9)^4
What is the first derivative of f(x)=(2x-9)^4(x^2+x+1)^5 ?
The first derivative of f(x)=(2x-9)^4(x^2+x+1)^5 is 8(2x-9)^3(x^2+x+1)^5+5(x^2+x+1)^4(2x+1)(2x-9)^4