What is derivative of f(x)=(2t+3)/(t+5) ?

The answer to derivative of f(x)=(2t+3)/(t+5) is (dt)/(dx)=0

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derivative of f(x)=(2t+3)/(t+5)

derivative of

f (x) = \frac{2 t + 3}{t + 5}

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{2 t + 3}{t + 5}

Treat

t

t (x)

Differentiate both sides:

0 = \frac{7 \frac{d t}{d x}}{( t + 5 ) ^{2}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{d ^{2}}{d x ^{2}} (t e^{- t})

\int x - 2 x d x

y = - 2 x^{3}, (- 1, 2)

\int_{0}^{1} \int_{0}^{1} 4 x y e^{- 2 x - y} d y d x

n = 0 \sum \infty (- 1)^{- n}

What is derivative of f(x)=(2t+3)/(t+5) ?
The answer to derivative of f(x)=(2t+3)/(t+5) is (dt)/(dx)=0