What is the derivative of cy^{-9} ?

The derivative of cy^{-9} is -(9c)/(y^{10)}

What is the first derivative of cy^{-9} ?

The first derivative of cy^{-9} is -(9c)/(y^{10)}

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derivative of

c y^{- 9}

- \frac{9 c}{y ^{10}}

Solution steps

\frac{d}{d y} (c y^{- 9})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d y} (y^{- 9})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= c (- 9 y^{- 9 - 1})

Simplify

c (- 9 y^{- 9 - 1}) : - \frac{9 c}{y ^{10}}

= - \frac{9 c}{y ^{10}}

\frac{\partial}{\partial x} (- \frac{1}{r})

\int (x^{2} - x y) d x

- 3 x^{- 4}

\frac{\partial}{\partial y} (x \cdot e^{x y})

(8 z + e^{- z^{2}})^{5}

What is the derivative of cy^{-9} ?
The derivative of cy^{-9} is -(9c)/(y^{10)}
What is the first derivative of cy^{-9} ?
The first derivative of cy^{-9} is -(9c)/(y^{10)}