What is the derivative of-3x^{-4} ?

The derivative of-3x^{-4} is (12)/(x^5)

What is the first derivative of-3x^{-4} ?

The first derivative of-3x^{-4} is (12)/(x^5)

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derivative of

- 3 x^{- 4}

\frac{12}{x ^{5}}

Solution steps

\frac{d}{d x} (- 3 x^{- 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 (- 4 x^{- 4 - 1})

Simplify

- 3 (- 4 x^{- 4 - 1}) : \frac{12}{x ^{5}}

= \frac{12}{x ^{5}}

\frac{\partial}{\partial y} (x \cdot e^{x y})

(8 z + e^{- z^{2}})^{5}

n = 4 \sum \infty \frac{3 ^{n}}{1 4 ^{n}}

\frac{\partial}{\partial x} (x^{2} e^{x y})

\int - 3 x + 2 d x

What is the derivative of-3x^{-4} ?
The derivative of-3x^{-4} is (12)/(x^5)
What is the first derivative of-3x^{-4} ?
The first derivative of-3x^{-4} is (12)/(x^5)