What is (\partial)/(\partial y)(x+y+z) ?

The answer to (\partial)/(\partial y)(x+y+z) is 1

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(\partial)/(\partial y)(x+y+z)

\frac{\partial}{\partial y} (x + y + z)

1

Solution steps

\frac{\partial}{\partial y} (x + y + z)

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (y) + \frac{\partial}{\partial y} (z)

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (z) = 0

= 0 + 1 + 0

Simplify

= 1

x \to - 2 lim (x - 2)

x, at x = 4

x \to \infty lim (x^{\frac{5}{x}})

\int_{0}^{π} sin (x) x^{5} d x

x \to - 2 - lim (\frac{- 4 x}{x + 2})

What is (\partial)/(\partial y)(x+y+z) ?
The answer to (\partial)/(\partial y)(x+y+z) is 1