What is the derivative of 3x^2+4x ?

The derivative of 3x^2+4x is 6x+4

What is the first derivative of 3x^2+4x ?

The first derivative of 3x^2+4x is 6x+4

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\frac{d}{d x} (3 x^{2} + 4 x)

6 x + 4

Solution steps

\frac{d}{d x} (3 x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

= 6 x + 4

\frac{d}{d x} ((x - 1) \cdot e^{x^{2} - 4})

\int x ln (a x) d x

\frac{d}{d x} (cos (x) cos (y))

\int_{1}^{4} \frac{x ^{2} + 2}{5 x - x ^{2}} d x

x (25.5)

What is the derivative of 3x^2+4x ?
The derivative of 3x^2+4x is 6x+4
What is the first derivative of 3x^2+4x ?
The first derivative of 3x^2+4x is 6x+4