What is the tangent of sqrt(x)(25.5) ?

The tangent of sqrt(x)(25.5) is y=(12.75}{sqrt(a_{0)}}x+\frac{51sqrt(a_{0)})/4

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tangent of sqrt(x)(25.5)

tangent of

x (25.5)

y = \frac{12.75}{a _{0}} x + \frac{51 a _{0}}{4}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0} \cdot 25.5)

Find the slope of

y = x 25.5 : \frac{d y}{d x} = \frac{12.75}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{12.75}{a _{0}}

Find the line with slope m=

\frac{12.75}{a _{0}}

and passing through

(a_{0}, a_{0} 25.5) : y = \frac{12.75}{a _{0}} x + \frac{51 a _{0}}{4}

y = \frac{12.75}{a _{0}} x + \frac{51 a _{0}}{4}

\frac{d}{d x} (x^{2} - 4 x - 2)

f (x) = \frac{4 x}{x + 2}, (2, 2)

\frac{\partial}{\partial x} (\frac{2 x + 2}{y ^{3}})

\frac{d}{d x} (5 x^{3} 25 - x^{2})

\frac{d y}{d x} = \frac{y - 1}{x ^{2}}

What is the tangent of sqrt(x)(25.5) ?
The tangent of sqrt(x)(25.5) is y=(12.75}{sqrt(a_{0)}}x+\frac{51sqrt(a_{0)})/4