What is the derivative of x^2-4x-2 ?

The derivative of x^2-4x-2 is 2x-4

What is the first derivative of x^2-4x-2 ?

The first derivative of x^2-4x-2 is 2x-4

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\frac{d}{d x} (x^{2} - 4 x - 2)

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (2) = 0

= 2 x - 4 - 0

Simplify

= 2 x - 4

f (x) = \frac{4 x}{x + 2}, (2, 2)

\frac{\partial}{\partial x} (\frac{2 x + 2}{y ^{3}})

\frac{d}{d x} (5 x^{3} 25 - x^{2})

\frac{d y}{d x} = \frac{y - 1}{x ^{2}}

\int x cos (x y) + 1 d y

What is the derivative of x^2-4x-2 ?
The derivative of x^2-4x-2 is 2x-4
What is the first derivative of x^2-4x-2 ?
The first derivative of x^2-4x-2 is 2x-4