What is (\partial)/(\partial x)(4e^xln(1+y)) ?

The answer to (\partial)/(\partial x)(4e^xln(1+y)) is 4ln(1+y)e^x

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(\partial)/(\partial x)(4e^xln(1+y))

\frac{\partial}{\partial x} (4 e^{x} ln (1 + y))

4 ln (1 + y) e^{x}

Solution steps

\frac{\partial}{\partial x} (4 e^{x} ln (1 + y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 ln (1 + y) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= 4 ln (1 + y) e^{x}

x \to \infty + lim ((1 + \frac{1}{x})^{\frac{x}{6}})

n = 6 \sum \infty \frac{n}{n ^{2} + 1}

\frac{\partial}{\partial y} (x^{2} y z^{2})

\int_{5}^{\infty} \frac{1}{x ^{3}} d x

\frac{\partial}{\partial x} (1 - ln (x))

What is (\partial)/(\partial x)(4e^xln(1+y)) ?
The answer to (\partial)/(\partial x)(4e^xln(1+y)) is 4ln(1+y)e^x