What is the derivative of-5/(4x^3) ?

The derivative of-5/(4x^3) is (15)/(4x^4)

What is the first derivative of-5/(4x^3) ?

The first derivative of-5/(4x^3) is (15)/(4x^4)

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\frac{d}{d x} (- \frac{5}{4 x ^{3}})

\frac{15}{4 x ^{4}}

Solution steps

\frac{d}{d x} (- \frac{5}{4 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{5}{4} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{5}{4} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{5}{4} (- 3 x^{- 3 - 1})

Simplify

- \frac{5}{4} (- 3 x^{- 3 - 1}) : \frac{15}{4 x ^{4}}

= \frac{15}{4 x ^{4}}

\frac{d}{d y} (\frac{y ^{2}}{2})

\frac{\partial}{\partial x} (cos (x^{2} + y^{2}))

\frac{d}{d x} (\frac{x}{4} (1 + ln (\frac{4}{x})))

\int (5 + x^{4}) sin (\frac{1}{2} x) d x

\int_{2}^{e^{5}} \frac{1}{x} d x

What is the derivative of-5/(4x^3) ?
The derivative of-5/(4x^3) is (15)/(4x^4)
What is the first derivative of-5/(4x^3) ?
The first derivative of-5/(4x^3) is (15)/(4x^4)