What is taylor sqrt(4x+1) ?

The answer to taylor sqrt(4x+1) is 1+2x-2x^2+4x^3-10x^4+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor sqrt(4x+1)

taylor

4 x + 1

1 + 2 x - 2 x^{2} + 4 x^{3} - 10 x^{4} + \dots

Solution steps

Apply the Taylor Formula

= 1 + \frac{\frac{d}{d x} ( 4 x + 1 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 4 x + 1 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 4 x + 1 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{2}{1 !} x + \frac{- 4}{2 !} x^{2} + \frac{24}{3 !} x^{3} + \frac{- 240}{4 !} x^{4} + \dots

Refine

= 1 + 2 x - 2 x^{2} + 4 x^{3} - 10 x^{4} + \dots

\frac{d}{d x} (1 - x^{\frac{3}{2}})

\int (2 x + 3)^{3} d x

\frac{d}{d x} (\frac{25 x ^{3}}{3} + 10 x^{2} + 4 x - 7)

f^{^{'}} (x) = e^{- 2 x}

\frac{d}{d x} (\frac{2 x + sin ( x )}{2 x + cos ( x )})

What is taylor sqrt(4x+1) ?
The answer to taylor sqrt(4x+1) is 1+2x-2x^2+4x^3-10x^4+\ldots