What is the derivative of 3x-4x^2 ?

The derivative of 3x-4x^2 is 3-8x

What is the first derivative of 3x-4x^2 ?

The first derivative of 3x-4x^2 is 3-8x

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derivative of

3 x - 4 x^{2}

3 - 8 x

Solution steps

\frac{d}{d x} (3 x - 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4 x^{2}) = 8 x

= 3 - 8 x

\int (x^{1.8} + 9 x^{3.5}) d x

(4 y + x^{2} y) d y - (2 x + x y^{2}) d x = 0

y^{^{''}} - y^{^{'}} - 2 y = 8 e^{- t}

\frac{d}{d x} ((- 2)^{x})

4 x^{- 1}

What is the derivative of 3x-4x^2 ?
The derivative of 3x-4x^2 is 3-8x
What is the first derivative of 3x-4x^2 ?
The first derivative of 3x-4x^2 is 3-8x