What is the solution for x*(dy)/(dx)+6y=x^3-x ?

The solution for x*(dy)/(dx)+6y=x^3-x is y=(x^3)/9-x/7+(c_{1})/(x^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x*(dy)/(dx)+6y=x^3-x

x \cdot \frac{d y}{d x} + 6 y = x^{3} - x

y = \frac{x ^{3}}{9} - \frac{x}{7} + \frac{c _{1}}{x ^{6}}

Solution steps

x \cdot \frac{d y}{d x} + 6 y = x^{3} - x

Solve linear ODE:

y = \frac{x ^{3}}{9} - \frac{x}{7} + \frac{c _{1}}{x ^{6}}

y = \frac{x ^{3}}{9} - \frac{x}{7} + \frac{c _{1}}{x ^{6}}

\frac{d}{d t} (4)

(\frac{2 t}{t ^{2} + 1})^{^{'}}

\frac{\partial}{\partial y} (x^{3} - 5 x y)

x \to 0 + lim (sin (x) ln (2 x))

\frac{d ^{3}}{d x ^{3}} (x^{4} - 4 x^{3})

What is the solution for x*(dy)/(dx)+6y=x^3-x ?
The solution for x*(dy)/(dx)+6y=x^3-x is y=(x^3)/9-x/7+(c_{1})/(x^6)