What is (\partial)/(\partial y)(x^3-5xy) ?

The answer to (\partial)/(\partial y)(x^3-5xy) is -5x

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(\partial)/(\partial y)(x^3-5xy)

\frac{\partial}{\partial y} (x^{3} - 5 x y)

- 5 x

Solution steps

\frac{\partial}{\partial y} (x^{3} - 5 x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{3}) - \frac{\partial}{\partial y} (5 x y)

\frac{\partial}{\partial y} (x^{3}) = 0

\frac{\partial}{\partial y} (5 x y) = 5 x

= 0 - 5 x

Simplify

= - 5 x

x \to 0 + lim (sin (x) ln (2 x))

\frac{d ^{3}}{d x ^{3}} (x^{4} - 4 x^{3})

x \to - 1 lim (\frac{1 - ∣ x ∣}{x + 1})

\frac{\partial}{\partial y} (cos (y) sin (x))

(- 3 t^{2}) (t - 2)

What is (\partial)/(\partial y)(x^3-5xy) ?
The answer to (\partial)/(\partial y)(x^3-5xy) is -5x