What is the tangent of y=(sqrt(x))/(x+3),(4, 2/7) ?

The tangent of y=(sqrt(x))/(x+3),(4, 2/7) is y=-1/196 x+15/49

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tangent of y=(sqrt(x))/(x+3),(4, 2/7)

tangent of

y = \frac{x}{x + 3}, (4, \frac{2}{7})

y = - \frac{1}{196} x + \frac{15}{49}

Solution steps

Find the slope of

y = \frac{x}{x + 3} : \frac{d y}{d x} = \frac{- x + 3}{2 x ( x + 3 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{196}

Find the line with slope m=

- \frac{1}{196}

and passing through

(4, \frac{2}{7}) : y = - \frac{1}{196} x + \frac{15}{49}

y = - \frac{1}{196} x + \frac{15}{49}

\frac{x ^{3}}{3} + \frac{3}{x ^{3}}

x \to \infty lim (6)

\int_{0}^{π} π sin^{4} (x) d x

x \to 2 lim (4)

\int (x + 4) (x - 5) d x

What is the tangent of y=(sqrt(x))/(x+3),(4, 2/7) ?
The tangent of y=(sqrt(x))/(x+3),(4, 2/7) is y=-1/196 x+15/49