What is (\partial)/(\partial x)(x^2-xyz) ?

The answer to (\partial)/(\partial x)(x^2-xyz) is 2x-yz

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(\partial)/(\partial x)(x^2-xyz)

\frac{\partial}{\partial x} (x^{2} - x yz)

2 x - yz

Solution steps

\frac{\partial}{\partial x} (x^{2} - x yz)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (x yz)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x yz) = yz

= 2 x - yz

y^{^{''}} - 3 y^{^{'}} - 4 y = - 8 e^{x} cos (2 x)

\int (e^{y^{2}}) d y

y = 3 x

f (x) = 2 x, (8, 4)

\frac{\partial}{\partial x} (x^{6} y - 4 x^{5} y^{2})

What is (\partial)/(\partial x)(x^2-xyz) ?
The answer to (\partial)/(\partial x)(x^2-xyz) is 2x-yz