What is (\partial)/(\partial y)(x-4y-9) ?

The answer to (\partial)/(\partial y)(x-4y-9) is -4

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(\partial)/(\partial y)(x-4y-9)

\frac{\partial}{\partial y} (x - 4 y - 9)

- 4

Solution steps

\frac{\partial}{\partial y} (x - 4 y - 9)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) - \frac{\partial}{\partial y} (4 y) - \frac{\partial}{\partial y} (9)

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (4 y) = 4

\frac{\partial}{\partial y} (9) = 0

= 0 - 4 - 0

Simplify

= - 4

\int (4 + 3 x)^{4} d x

n = 1 \sum \infty \frac{n - 1}{2 n + 1}

cos (x^{- 9})

\frac{d}{d x} (3 - \frac{7}{2 x ^{\frac{1}{8}}})

x^{2} + y^{2} = 4, x^{2} + y^{2} = 4 x

What is (\partial)/(\partial y)(x-4y-9) ?
The answer to (\partial)/(\partial y)(x-4y-9) is -4