What is (\partial)/(\partial x)(bcos(wx)+csin(wx)) ?

The answer to (\partial)/(\partial x)(bcos(wx)+csin(wx)) is -bwsin(wx)+iwcsn

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(\partial)/(\partial x)(bcos(wx)+csin(wx))

\frac{\partial}{\partial x} (b cos (w x) + cs in (w x))

- b w sin (w x) + i w cs n

Solution steps

\frac{\partial}{\partial x} (b cos (w x) + cs in (w x))

Treat

n, b, w, c, s

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (b cos (w x)) + \frac{\partial}{\partial x} (cs in w x)

\frac{\partial}{\partial x} (b cos (w x)) = - b w sin (w x)

\frac{\partial}{\partial x} (cs in w x) = i w cs n

= - b w sin (w x) + i w cs n

n = 0 \sum \infty (\frac{- 6 + 7}{2})^{n}

g (x) = - x^{2} + 4 x^{2} - 2 x + 2

x^{2} - 4 x, 2 x + 7

\int cos (x) + \frac{1}{9} x d x

\int_{0}^{5} \frac{x}{9 - x} d x

What is (\partial)/(\partial x)(bcos(wx)+csin(wx)) ?
The answer to (\partial)/(\partial x)(bcos(wx)+csin(wx)) is -bwsin(wx)+iwcsn